IBPS PO MAINS MATHS

Advanced Quant    

Here is a quiz for upcoming Banking exams like IBPS PO. so make sure you attempt today’s Quant IBPS PO Mains to check your preparation level.

Advanced IBPS PO Mains Quiz

Que. 1

Pipe A can fill a tank in 8 hours and pipe B can empty the full tank in 12 hour. How much time will it take to fill the tank if both the pipes are opened simultaneously?

1. 18 hours

2. 12 hours

3. 10 hours

4. 24 hours

5. None of these

Que. 2

In how many different ways can the letters of the word ‘PADDLED’ be arranged?

1. 490

2. 2570

3. 1680

4. 840

5. None of these

Que. 3

2 numbers are in the ratio 5 : 3.If they differ by 18 what in the product of the two numbers?

1. 9

2. 133

3.243

4. 1215

5. 403

Que. 4

A sum of money doubles itself at compound interest in 15 years. In how many years it will become eight times?

1. 30

2.45

3. 50

4. 60

5. None of these

Que. 5

What will be the area of a semi – circle whose perimeter is 66 cm?

1. 693 cm2

2. 646 cm2

3.521 cm2

4. 505 cm2

5. None of these

Que. 6

Average age of 12 men is increased by 2 yr when one man whose age is 41 yr is replaced by a new man. Find the age of the new man.

1. 61 yr

2. 63 yr

3. 65 yr

4. 67 yr

5. None of these

Solution

Que. 7

What will come in place of question mark (?) in the following number series?

30              25        ?              18           16           15

1. 20

2.21

3. 24

4. 15

5. 18

Solution

Que. 8

Ravi mixes 80 kg of wheat worth of Rs. 6.75 per kg with 120 kg worth of Rs. 8 per kg. At what rate shall he sell the mixture to gain 20%?

1. Rs. 7.50

2. Rs. 9.00

3. Rs. 8.20

4. Rs. 8.85

5. None of these

Que. 9

P, Q and R can do a piece of work in 15, 20 and 30 days. They undertake to complete the work for Rs. 810. How much share of P exceeds that of Q?

1. Rs. 90

2. Rs. 180

3. Rs. 270

4. Rs. 360

5. None of these

Que. 10

A bag contains 3 blue, 2 green and 5 red balls. If four balls are picked at random, what is the probability that two are green and two are blue?

1.3/10

2.1/120

3.1/70

4.3/70

5. None of these

Answers:

1.  ⇒ Tank filled by pipe A in one hour = 1/8

⇒ Tank emptied by pope B in one hour = 1/12

⇒ Tank filled in one hour =(1/8) – (1/12) = 1/24

⇒ Tank will be filled in 24 hours.

2.  840

3. Let one of the numbers be 5x

∴The other number must be 3x

∴ Difference = 18

∴ 5x - 3x = 18

∴ x = 9

∴The numbers = 45 and 27

∴ Product = 1215

4.

    T = 45 years

5. we know that

Area of the semi-circle = π×r22

Perimeter of semi-circle = π × r + 2× r

According to the question

π × r + 2× r = 66 cm

⇒ r × [π +2] = 66

⇒ r = 12.83

∴ Area of the semi-circle = [π × (12.83)2]/2 = 258.56 cm2

So the correct answer is (5).

6.

Let the Average of age of the 12 persons be x

Average = {(Sum total of individual value of n things) / (total no of things i.e. n)}

Here the formula transforms accordingly to

Now Average of Age = (Sum of Age of all persons / No. of Persons)

⇒ x = (Total Age of all persons / 12)

⇒ Total Age of all persons = 12x

Let the age of new person entering the group be y yrs

According to question one person having Age = y yrs is added to the group while the person having age =41 years left the group, so the total age now becomes = (12x + y- 41)

And new average becomes = (x + 2)

(i.e. 2 more than the original)

⇒ ((12x + y - 41) / 12) = (x + 2)

⇒ 12x + y - 41 = 12x + 24

⇒ y = 24 + 41 = 65

⇒ y = 65

7.   required term is 21.

8. The Cost price of Mixture is

×Price1) + (Weight2×Price2)} / (Weight1 + Weight2)

⇒ {(6.75 × 80) + (8 × 120)} / (80+120)

⇒ {540 + 960} / 200

⇒ 1500/200 = Rs. 7.5/kg

Gain = 20%

Gain% = (Gain × 100)/C.P.

⇒ 20 = (Gain × 100)/C.P.

⇒ (1/5) × C.P. = Gain = S.P. - C.P.

⇒ (1/5) × 7.5 = S.P. - 7.5

⇒ S.P. = 1.5 + 7.5

⇒ S.P. = 9

9.   If P takes 15 days to complete a work

⇒ he will complete (1/15)th of the work in a single day

If Q takes 20 days to complete a work

⇒ he will complete (1/20)th of the work in a single day

If R takes 30 days to complete a work

⇒ he will complete (1/30)th of the work in a single day

Together in a single day amount of work completed = (1/15)+(1/20)+(1/30) = (9/60)

Let P's share of work done = x

x of (9/60) = (1/15)

⇒ (x) × (9/60) = (1/15)

⇒ x = 4/9

Let Q's share of work done = y

y of (9/60) = (1/20)

⇒ y × (9/60) = (1/20)

⇒ y = (3/9)

Let R's share of work done = z

z of (9/60) = (1/30)

⇒ (z) × (9/60) = (1/30)

⇒ z = (2/9)

Distribution of wages as per the work done

P's share = (4/9) × 810 = Rs 360

Q's share = (3/9) × 810 = Rs 270

R's share = (2/9) × 810 = Rs 180

P's Share exceeds Q's share by (360-270) = Rs 90

10

If 4 balls are picked out of 10 balls,

⇒ Sample space n(S)=10C4=210

To get two green and two blue balls,

Favourable Case n(E)=3C2×2C2=3

⇒ Required probability =n(E)n(S)=3210

= 1/70

Hence, the required probability to get two green and two blue balls would be 1/70.